Question 1

An automobile company manufactures both a two wheeler (TW) and a four wheeler (FW). A company manager wants to make the production of both types of vehicle according to the given Data below: 1st data, Total number of vehicle (two-wheeler + four-wheeler)=v 2nd data, Total number of wheels = W The task is to find how many two-wheelers as well as four-wheelers need to manufacture as per the given data. Example : Input : 200 -> Value of V 540 -> Value of W Output : TW =130 FW=70

#include <bits/stdc++.h> using namespace std; Explanation: 130+70 = 200 vehicles (704)+(1302)= 540 wheels Constraints : 2<=W W%2=0 V<W Print “INVALID INPUT” , if inputs did not meet the constraints. The input format for testing The candidate has to write the code to accept two positive numbers separated by a new line. First Input line - Accept value of V. Second Input line- Accept value for W. The output format for testing Written program code should generate two outputs, each separated by a single space Character(see the example) Additional messages in the output will result in the failure of test case Solution: in C++:

v=int(input()) w=int(input()) if (w&1)==1 or w<2 or w<=v: print(“INVALID INPUT”) else: x=((4v) -w)//2 print(“TW={0} FW={1}”.format(x,v-x)) int main() { int v,w; cin>>v>>w; float x=((4v)-w)/2; if((w&1) || w<2 || w<=v) {cout<<“INVALID INPUT”; return 0;} Cout<<“TW=”<<x<<“ “<<“FW=”<<v-x; } Solution: in Python:

Solution: in Java:

import java.util.*; public class Solution { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int v=sc.nextInt();

int w=sc.nextInt(); float res=((4*v)-w)/2; if(w>=2 && (w%2==0) && v<w ) System.out.println(“TW= “+(int)(res)+” FW= “+(int)(v-res)); else System.out.println(“INVALID INPUT”); } }