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Pattern 2: 3. Medium: Rotate Image

DSA Patterns

Description: Rotate a given n x n 2D matrix by 90 degrees (clockwise).

Java

public void rotate(int[][] matrix) {

int n = matrix.length; for (int i = 0; i < n / 2; i++) { for (int j = i; j < n - i - 1; j++) { int temp = matrix[i][j]; matrix[i][j] = matrix[n - j - 1][i]; matrix[n - j - 1][i] = matrix[n - i - 1][n - j - 1]; matrix[n - i - 1][n - j - 1] = matrix[j][n - i - 1]; matrix[j][n - i - 1] = temp; } } }

C++

void rotate(vector<vector<int>>& matrix)
{ int n = matrix.size();
for (int i = 0; i < n / 2; i++) {
for (int j = i; j < n - i - 1; j++)
{ int temp = matrix[i][j];
matrix[i][j] = matrix[n - j - 1][i];
matrix[n - j - 1][i] = matrix[n - i - 1][n - j - 1];
matrix[n - i - 1][n - j - 1] = matrix[j][n - i - 1];
matrix[j][n - i - 1] = temp;
}
}
}

Python

def rotate(matrix):
n = len(matrix)
for i in range(n // 2):
for j in range(i, n - i - 1):
temp = matrix[i][j]
matrix[i][j] = matrix[n - j - 1][i]

matrix[n - j - 1][i] = matrix[n - i - 1][n - j - 1] matrix[n - i - 1][n - j - 1] = matrix[j][n - i - 1] matrix[j][n - i - 1] = temp

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